3=33+3(x^2)

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Solution for 3=33+3(x^2) equation: 



3=33+3(x^2)

We move all terms to the left:

3-(33+3(x^2))=0

We get rid of parentheses

-3x^2-33+3=0

We add all the numbers together, and all the variables

-3x^2-30=0

a = -3; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·(-3)·(-30)
Δ = -360
Delta is less than zero, so there is no solution for the equation

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